3b2+7b+2=0

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Solution for 3b2+7b+2=0 equation: 



3b^2+7b+2=0

a = 3; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·3·2
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*3}=\frac{-12}{6}
=-2
$


$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*3}=\frac{-2}{6}
=-1/3
$

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