3b2-14b-20=4

Solution for 3b2-14b-20=4 equation:

3b^2-14b-20=4

We move all terms to the left:

3b^2-14b-20-(4)=0

We add all the numbers together, and all the variables

3b^2-14b-24=0

a = 3; b = -14; c = -24;
Δ = b2-4ac
Δ = -142-4·3·(-24)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-22}{2*3}=\frac{-8}{6}
=-1+1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+22}{2*3}=\frac{36}{6}
=6
$