3b2-34=-11b

Solution for 3b2-34=-11b equation:

3b^2-34=-11b

We move all terms to the left:

3b^2-34-(-11b)=0

We get rid of parentheses

3b^2+11b-34=0

a = 3; b = 11; c = -34;
Δ = b2-4ac
Δ = 112-4·3·(-34)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-23}{2*3}=\frac{-34}{6}
=-5+2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+23}{2*3}=\frac{12}{6}
=2
$