3b=(13c-10)/3a

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Solution for 3b=(13c-10)/3a equation:


x in (-oo:+oo)

3*b = a*((13*c-10)/3) // - a*((13*c-10)/3)

3*b-(a*((13*c-10)/3)) = 0

(-1*a*(13*c-10))/3+3*b = 0

(-1*a*(13*c-10))/3+(3*3*b)/3 = 0

3*3*b-1*a*(13*c-10) = 0

10*a+9*b-13*a*c = 0

(10*a+9*b-13*a*c)/3 = 0

(10*a+9*b-13*a*c)/3 = 0 // * 3

10*a+9*b-13*a*c = 0

x belongs to the empty set

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