3b=(b+84)

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Solution for 3b=(b+84) equation: 



3b=(b+84)

We move all terms to the left:

3b-((b+84))=0



We calculate terms in parentheses: -((b+84)), so:

(b+84)

We get rid of parentheses

b+84

Back to the equation:

-(b+84)



We get rid of parentheses

3b-b-84=0

We add all the numbers together, and all the variables

2b-84=0

We move all terms containing b to the left, all other terms to the right

2b=84

b=84/2

b=42

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