3c(2n+3)=2n+21

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Solution for 3c(2n+3)=2n+21 equation:


Simplifying
3c(2n + 3) = 2n + 21

Reorder the terms:
3c(3 + 2n) = 2n + 21
(3 * 3c + 2n * 3c) = 2n + 21
(9c + 6cn) = 2n + 21

Reorder the terms:
9c + 6cn = 21 + 2n

Solving
9c + 6cn = 21 + 2n

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Reorder the terms:
-21 + 9c + 6cn + -2n = 21 + 2n + -21 + -2n

Reorder the terms:
-21 + 9c + 6cn + -2n = 21 + -21 + 2n + -2n

Combine like terms: 21 + -21 = 0
-21 + 9c + 6cn + -2n = 0 + 2n + -2n
-21 + 9c + 6cn + -2n = 2n + -2n

Combine like terms: 2n + -2n = 0
-21 + 9c + 6cn + -2n = 0

The solution to this equation could not be determined.

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