3c(3c-1)=2

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Solution for 3c(3c-1)=2 equation:


Simplifying
3c(3c + -1) = 2

Reorder the terms:
3c(-1 + 3c) = 2
(-1 * 3c + 3c * 3c) = 2
(-3c + 9c2) = 2

Solving
-3c + 9c2 = 2

Solving for variable 'c'.

Reorder the terms:
-2 + -3c + 9c2 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -3c + 9c2 = 0

Factor a trinomial.
(-1 + -3c)(2 + -3c) = 0

Subproblem 1

Set the factor '(-1 + -3c)' equal to zero and attempt to solve: Simplifying -1 + -3c = 0 Solving -1 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -3c = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -3c = 0 + 1 -3c = 0 + 1 Combine like terms: 0 + 1 = 1 -3c = 1 Divide each side by '-3'. c = -0.3333333333 Simplifying c = -0.3333333333

Subproblem 2

Set the factor '(2 + -3c)' equal to zero and attempt to solve: Simplifying 2 + -3c = 0 Solving 2 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -3c = 0 + -2 -3c = 0 + -2 Combine like terms: 0 + -2 = -2 -3c = -2 Divide each side by '-3'. c = 0.6666666667 Simplifying c = 0.6666666667

Solution

c = {-0.3333333333, 0.6666666667}

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