3c(5-2)+8=3(c-4)+1

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Solution for 3c(5-2)+8=3(c-4)+1 equation: 



3c(5-2)+8=3(c-4)+1

We move all terms to the left:

3c(5-2)+8-(3(c-4)+1)=0

We add all the numbers together, and all the variables

3c3-(3(c-4)+1)+8=0

We add all the numbers together, and all the variables

3c^3-(3(c-4)+1)+8=0



We calculate terms in parentheses: -(3(c-4)+1), so:

3(c-4)+1

We multiply parentheses

3c-12+1

We add all the numbers together, and all the variables

3c-11

Back to the equation:

-(3c-11)



We do not support ecpression: c^3

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