3c(6-2c)=27

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Solution for 3c(6-2c)=27 equation: 



3c(6-2c)=27

We move all terms to the left:

3c(6-2c)-(27)=0

We add all the numbers together, and all the variables

3c(-2c+6)-27=0

We multiply parentheses

-6c^2+18c-27=0

a = -6; b = 18; c = -27;
Δ = b2-4ac
Δ = 182-4·(-6)·(-27)
Δ = -324
Delta is less than zero, so there is no solution for the equation

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