3c(z-b)=12

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Solution for 3c(z-b)=12 equation:


Simplifying
3c(z + -1b) = 12

Reorder the terms:
3c(-1b + z) = 12
(-1b * 3c + z * 3c) = 12
(-3bc + 3cz) = 12

Solving
-3bc + 3cz = 12

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3cz' to each side of the equation.
-3bc + 3cz + -3cz = 12 + -3cz

Combine like terms: 3cz + -3cz = 0
-3bc + 0 = 12 + -3cz
-3bc = 12 + -3cz

Divide each side by '-3c'.
b = -4c-1 + z

Simplifying
b = -4c-1 + z

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