3c*3c=48

Solution for 3c*3c=48 equation:

3c*3c=48

We move all terms to the left:

3c*3c-(48)=0

Wy multiply elements

9c^2-48=0

a = 9; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·9·(-48)
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*9}=\frac{0-24\sqrt{3}}{18}
=-\frac{24\sqrt{3}}{18}
=-\frac{4\sqrt{3}}{3}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*9}=\frac{0+24\sqrt{3}}{18}
=\frac{24\sqrt{3}}{18}
=\frac{4\sqrt{3}}{3}
$