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3c+(-12)=6
We move all terms to the left:
3c+(-12)-(6)=0
determiningTheFunctionDomain 3c-6+(-12)=0
We add all the numbers together, and all the variables
3c-18=0
We move all terms containing c to the left, all other terms to the right
3c=18
c=18/3
c=6
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