3c+(c+2)=13(2c-5)

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Solution for 3c+(c+2)=13(2c-5) equation:


Simplifying
3c + (c + 2) = 13(2c + -5)

Reorder the terms:
3c + (2 + c) = 13(2c + -5)

Remove parenthesis around (2 + c)
3c + 2 + c = 13(2c + -5)

Reorder the terms:
2 + 3c + c = 13(2c + -5)

Combine like terms: 3c + c = 4c
2 + 4c = 13(2c + -5)

Reorder the terms:
2 + 4c = 13(-5 + 2c)
2 + 4c = (-5 * 13 + 2c * 13)
2 + 4c = (-65 + 26c)

Solving
2 + 4c = -65 + 26c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-26c' to each side of the equation.
2 + 4c + -26c = -65 + 26c + -26c

Combine like terms: 4c + -26c = -22c
2 + -22c = -65 + 26c + -26c

Combine like terms: 26c + -26c = 0
2 + -22c = -65 + 0
2 + -22c = -65

Add '-2' to each side of the equation.
2 + -2 + -22c = -65 + -2

Combine like terms: 2 + -2 = 0
0 + -22c = -65 + -2
-22c = -65 + -2

Combine like terms: -65 + -2 = -67
-22c = -67

Divide each side by '-22'.
c = 3.045454545

Simplifying
c = 3.045454545

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