3c+(c+3)+(2c+3)=180

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Solution for 3c+(c+3)+(2c+3)=180 equation: 



3c+(c+3)+(2c+3)=180

We move all terms to the left:

3c+(c+3)+(2c+3)-(180)=0

We get rid of parentheses

3c+c+2c+3+3-180=0

We add all the numbers together, and all the variables

6c-174=0

We move all terms containing c to the left, all other terms to the right

6c=174

c=174/6

c=29

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