3c+1+5(c-2)=0

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Solution for 3c+1+5(c-2)=0 equation: 



3c+1+5(c-2)=0

We multiply parentheses

3c+5c-10+1=0

We add all the numbers together, and all the variables

8c-9=0

We move all terms containing c to the left, all other terms to the right

8c=9

c=9/8

c=1+1/8

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