3c+12+5c=28

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Solution for 3c+12+5c=28 equation: 



3c+12+5c=28

We move all terms to the left:

3c+12+5c-(28)=0

We add all the numbers together, and all the variables

8c-16=0

We move all terms containing c to the left, all other terms to the right

8c=16

c=16/8

c=2

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