3c+12-2c=16-4c-20

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Solution for 3c+12-2c=16-4c-20 equation: 



3c+12-2c=16-4c-20

We move all terms to the left:

3c+12-2c-(16-4c-20)=0

We add all the numbers together, and all the variables

3c-2c-(-4c-4)+12=0

We add all the numbers together, and all the variables

c-(-4c-4)+12=0

We get rid of parentheses

c+4c+4+12=0

We add all the numbers together, and all the variables

5c+16=0

We move all terms containing c to the left, all other terms to the right

5c=-16

c=-16/5

c=-3+1/5

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