3c+12=5c+10.02

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Solution for 3c+12=5c+10.02 equation: 



3c+12=5c+10.02

We move all terms to the left:

3c+12-(5c+10.02)=0

We get rid of parentheses

3c-5c-10.02+12=0

We add all the numbers together, and all the variables

-2c+1.98=0

We move all terms containing c to the left, all other terms to the right

-2c=-1.98

c=-1.98/-2

c=1/1.010101010101

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