3c+13=11+27c

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Solution for 3c+13=11+27c equation:



3c+13=11+27c
We move all terms to the left:
3c+13-(11+27c)=0
We add all the numbers together, and all the variables
3c-(27c+11)+13=0
We get rid of parentheses
3c-27c-11+13=0
We add all the numbers together, and all the variables
-24c+2=0
We move all terms containing c to the left, all other terms to the right
-24c=-2
c=-2/-24
c=1/12

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