3c+14-5c=-2(3c+1)

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Solution for 3c+14-5c=-2(3c+1) equation: 



3c+14-5c=-2(3c+1)

We move all terms to the left:

3c+14-5c-(-2(3c+1))=0

We add all the numbers together, and all the variables

-2c-(-2(3c+1))+14=0



We calculate terms in parentheses: -(-2(3c+1)), so:

-2(3c+1)

We multiply parentheses

-6c-2

Back to the equation:

-(-6c-2)



We get rid of parentheses

-2c+6c+2+14=0

We add all the numbers together, and all the variables

4c+16=0

We move all terms containing c to the left, all other terms to the right

4c=-16

c=-16/4

c=-4

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