3c+15=15+4c-2

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Solution for 3c+15=15+4c-2 equation: 



3c+15=15+4c-2

We move all terms to the left:

3c+15-(15+4c-2)=0

We add all the numbers together, and all the variables

3c-(4c+13)+15=0

We get rid of parentheses

3c-4c-13+15=0

We add all the numbers together, and all the variables

-1c+2=0

We move all terms containing c to the left, all other terms to the right

-c=-2

c=-2/-1

c=+2

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