3c+15=22c+17

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Solution for 3c+15=22c+17 equation: 



3c+15=22c+17

We move all terms to the left:

3c+15-(22c+17)=0

We get rid of parentheses

3c-22c-17+15=0

We add all the numbers together, and all the variables

-19c-2=0

We move all terms containing c to the left, all other terms to the right

-19c=2

c=2/-19

c=-2/19

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