3c+16-10c=-28-19c-3

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Solution for 3c+16-10c=-28-19c-3 equation: 



3c+16-10c=-28-19c-3

We move all terms to the left:

3c+16-10c-(-28-19c-3)=0

We add all the numbers together, and all the variables

3c-10c-(-19c-31)+16=0

We add all the numbers together, and all the variables

-7c-(-19c-31)+16=0

We get rid of parentheses

-7c+19c+31+16=0

We add all the numbers together, and all the variables

12c+47=0

We move all terms containing c to the left, all other terms to the right

12c=-47

c=-47/12

c=-3+11/12

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