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3c+1=1+c
We move all terms to the left:
3c+1-(1+c)=0
We add all the numbers together, and all the variables
3c-(c+1)+1=0
We get rid of parentheses
3c-c-1+1=0
We add all the numbers together, and all the variables
2c=0
c=0/2
c=0
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