3c+2(c+2)=-6

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Solution for 3c+2(c+2)=-6 equation: 



3c+2(c+2)=-6

We move all terms to the left:

3c+2(c+2)-(-6)=0

We add all the numbers together, and all the variables

3c+2(c+2)+6=0

We multiply parentheses

3c+2c+4+6=0

We add all the numbers together, and all the variables

5c+10=0

We move all terms containing c to the left, all other terms to the right

5c=-10

c=-10/5

c=-2

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