3c+2(c+2)=13-(2c-5)

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Solution for 3c+2(c+2)=13-(2c-5) equation:


Simplifying
3c + 2(c + 2) = 13 + -1(2c + -5)

Reorder the terms:
3c + 2(2 + c) = 13 + -1(2c + -5)
3c + (2 * 2 + c * 2) = 13 + -1(2c + -5)
3c + (4 + 2c) = 13 + -1(2c + -5)

Reorder the terms:
4 + 3c + 2c = 13 + -1(2c + -5)

Combine like terms: 3c + 2c = 5c
4 + 5c = 13 + -1(2c + -5)

Reorder the terms:
4 + 5c = 13 + -1(-5 + 2c)
4 + 5c = 13 + (-5 * -1 + 2c * -1)
4 + 5c = 13 + (5 + -2c)

Combine like terms: 13 + 5 = 18
4 + 5c = 18 + -2c

Solving
4 + 5c = 18 + -2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2c' to each side of the equation.
4 + 5c + 2c = 18 + -2c + 2c

Combine like terms: 5c + 2c = 7c
4 + 7c = 18 + -2c + 2c

Combine like terms: -2c + 2c = 0
4 + 7c = 18 + 0
4 + 7c = 18

Add '-4' to each side of the equation.
4 + -4 + 7c = 18 + -4

Combine like terms: 4 + -4 = 0
0 + 7c = 18 + -4
7c = 18 + -4

Combine like terms: 18 + -4 = 14
7c = 14

Divide each side by '7'.
c = 2

Simplifying
c = 2

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