3c+42+c+47=10c

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Solution for 3c+42+c+47=10c equation: 



3c+42+c+47=10c

We move all terms to the left:

3c+42+c+47-(10c)=0

We add all the numbers together, and all the variables

-6c+89=0

We move all terms containing c to the left, all other terms to the right

-6c=-89

c=-89/-6

c=14+5/6

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