3c+42=15

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Solution for 3c+42=15 equation: 



3c+42=15

We move all terms to the left:

3c+42-(15)=0

We add all the numbers together, and all the variables

3c+27=0

We move all terms containing c to the left, all other terms to the right

3c=-27

c=-27/3

c=-9

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