3c+4=2(c-5)

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Solution for 3c+4=2(c-5) equation:


Simplifying
3c + 4 = 2(c + -5)

Reorder the terms:
4 + 3c = 2(c + -5)

Reorder the terms:
4 + 3c = 2(-5 + c)
4 + 3c = (-5 * 2 + c * 2)
4 + 3c = (-10 + 2c)

Solving
4 + 3c = -10 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
4 + 3c + -2c = -10 + 2c + -2c

Combine like terms: 3c + -2c = 1c
4 + 1c = -10 + 2c + -2c

Combine like terms: 2c + -2c = 0
4 + 1c = -10 + 0
4 + 1c = -10

Add '-4' to each side of the equation.
4 + -4 + 1c = -10 + -4

Combine like terms: 4 + -4 = 0
0 + 1c = -10 + -4
1c = -10 + -4

Combine like terms: -10 + -4 = -14
1c = -14

Divide each side by '1'.
c = -14

Simplifying
c = -14

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