3c+5-2c=2(c-6)

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Solution for 3c+5-2c=2(c-6) equation: 



3c+5-2c=2(c-6)

We move all terms to the left:

3c+5-2c-(2(c-6))=0

We add all the numbers together, and all the variables

c-(2(c-6))+5=0



We calculate terms in parentheses: -(2(c-6)), so:

2(c-6)

We multiply parentheses

2c-12

Back to the equation:

-(2c-12)



We get rid of parentheses

c-2c+12+5=0

We add all the numbers together, and all the variables

-1c+17=0

We move all terms containing c to the left, all other terms to the right

-c=-17

c=-17/-1

c=+17

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