3c+56=7c+12

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Solution for 3c+56=7c+12 equation: 



3c+56=7c+12

We move all terms to the left:

3c+56-(7c+12)=0

We get rid of parentheses

3c-7c-12+56=0

We add all the numbers together, and all the variables

-4c+44=0

We move all terms containing c to the left, all other terms to the right

-4c=-44

c=-44/-4

c=+11

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