3c+6=14c+50

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Solution for 3c+6=14c+50 equation: 



3c+6=14c+50

We move all terms to the left:

3c+6-(14c+50)=0

We get rid of parentheses

3c-14c-50+6=0

We add all the numbers together, and all the variables

-11c-44=0

We move all terms containing c to the left, all other terms to the right

-11c=44

c=44/-11

c=-4

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