3c+7=4(c+1)

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Solution for 3c+7=4(c+1) equation:



3c+7=4(c+1)
We move all terms to the left:
3c+7-(4(c+1))=0
We calculate terms in parentheses: -(4(c+1)), so:
4(c+1)
We multiply parentheses
4c+4
Back to the equation:
-(4c+4)
We get rid of parentheses
3c-4c-4+7=0
We add all the numbers together, and all the variables
-1c+3=0
We move all terms containing c to the left, all other terms to the right
-c=-3
c=-3/-1
c=+3

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