3c-(c+2)=2

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Solution for 3c-(c+2)=2 equation: 



3c-(c+2)=2

We move all terms to the left:

3c-(c+2)-(2)=0

We get rid of parentheses

3c-c-2-2=0

We add all the numbers together, and all the variables

2c-4=0

We move all terms containing c to the left, all other terms to the right

2c=4

c=4/2

c=2

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