3c-(c+2)=2(4c+5)

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Solution for 3c-(c+2)=2(4c+5) equation:


Simplifying
3c + -1(c + 2) = 2(4c + 5)

Reorder the terms:
3c + -1(2 + c) = 2(4c + 5)
3c + (2 * -1 + c * -1) = 2(4c + 5)
3c + (-2 + -1c) = 2(4c + 5)

Reorder the terms:
-2 + 3c + -1c = 2(4c + 5)

Combine like terms: 3c + -1c = 2c
-2 + 2c = 2(4c + 5)

Reorder the terms:
-2 + 2c = 2(5 + 4c)
-2 + 2c = (5 * 2 + 4c * 2)
-2 + 2c = (10 + 8c)

Solving
-2 + 2c = 10 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
-2 + 2c + -8c = 10 + 8c + -8c

Combine like terms: 2c + -8c = -6c
-2 + -6c = 10 + 8c + -8c

Combine like terms: 8c + -8c = 0
-2 + -6c = 10 + 0
-2 + -6c = 10

Add '2' to each side of the equation.
-2 + 2 + -6c = 10 + 2

Combine like terms: -2 + 2 = 0
0 + -6c = 10 + 2
-6c = 10 + 2

Combine like terms: 10 + 2 = 12
-6c = 12

Divide each side by '-6'.
c = -2

Simplifying
c = -2

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