3c-11=5(c+1)

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Solution for 3c-11=5(c+1) equation: 



3c-11=5(c+1)

We move all terms to the left:

3c-11-(5(c+1))=0



We calculate terms in parentheses: -(5(c+1)), so:

5(c+1)

We multiply parentheses

5c+5

Back to the equation:

-(5c+5)



We get rid of parentheses

3c-5c-5-11=0

We add all the numbers together, and all the variables

-2c-16=0

We move all terms containing c to the left, all other terms to the right

-2c=16

c=16/-2

c=-8

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