3c-12=20+c

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Solution for 3c-12=20+c equation:



3c-12=20+c
We move all terms to the left:
3c-12-(20+c)=0
We add all the numbers together, and all the variables
3c-(c+20)-12=0
We get rid of parentheses
3c-c-20-12=0
We add all the numbers together, and all the variables
2c-32=0
We move all terms containing c to the left, all other terms to the right
2c=32
c=32/2
c=16

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