3c-13=5(2c+7)

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Solution for 3c-13=5(2c+7) equation: 



3c-13=5(2c+7)

We move all terms to the left:

3c-13-(5(2c+7))=0



We calculate terms in parentheses: -(5(2c+7)), so:

5(2c+7)

We multiply parentheses

10c+35

Back to the equation:

-(10c+35)



We get rid of parentheses

3c-10c-35-13=0

We add all the numbers together, and all the variables

-7c-48=0

We move all terms containing c to the left, all other terms to the right

-7c=48

c=48/-7

c=-6+6/7

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