3c-2(-6c+1)=-18+3c

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Solution for 3c-2(-6c+1)=-18+3c equation: 



3c-2(-6c+1)=-18+3c

We move all terms to the left:

3c-2(-6c+1)-(-18+3c)=0

We add all the numbers together, and all the variables

3c-2(-6c+1)-(3c-18)=0

We multiply parentheses

3c+12c-(3c-18)-2=0

We get rid of parentheses

3c+12c-3c+18-2=0

We add all the numbers together, and all the variables

12c+16=0

We move all terms containing c to the left, all other terms to the right

12c=-16

c=-16/12

c=-1+1/3

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