3c-2(3-2c)=3c-4c=-1c

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Solution for 3c-2(3-2c)=3c-4c=-1c equation: 



3c-2(3-2c)=3c-4c=-1c

We move all terms to the left:

3c-2(3-2c)-(3c-4c)=0

We add all the numbers together, and all the variables

3c-2(-2c+3)-(-1c)=0

We multiply parentheses

3c+4c-(-1c)-6=0

We get rid of parentheses

3c+4c+1c-6=0

We add all the numbers together, and all the variables

8c-6=0

We move all terms containing c to the left, all other terms to the right

8c=6

c=6/8

c=3/4

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