3c-2(4-3c)+5=2-c

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Solution for 3c-2(4-3c)+5=2-c equation: 



3c-2(4-3c)+5=2-c

We move all terms to the left:

3c-2(4-3c)+5-(2-c)=0

We add all the numbers together, and all the variables

3c-2(-3c+4)-(-1c+2)+5=0

We multiply parentheses

3c+6c-(-1c+2)-8+5=0

We get rid of parentheses

3c+6c+1c-2-8+5=0

We add all the numbers together, and all the variables

10c-5=0

We move all terms containing c to the left, all other terms to the right

10c=5

c=5/10

c=1/2

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