3c-2(c+10)=7c-5(c+2)

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Solution for 3c-2(c+10)=7c-5(c+2) equation:


Simplifying
3c + -2(c + 10) = 7c + -5(c + 2)

Reorder the terms:
3c + -2(10 + c) = 7c + -5(c + 2)
3c + (10 * -2 + c * -2) = 7c + -5(c + 2)
3c + (-20 + -2c) = 7c + -5(c + 2)

Reorder the terms:
-20 + 3c + -2c = 7c + -5(c + 2)

Combine like terms: 3c + -2c = 1c
-20 + 1c = 7c + -5(c + 2)

Reorder the terms:
-20 + 1c = 7c + -5(2 + c)
-20 + 1c = 7c + (2 * -5 + c * -5)
-20 + 1c = 7c + (-10 + -5c)

Reorder the terms:
-20 + 1c = -10 + 7c + -5c

Combine like terms: 7c + -5c = 2c
-20 + 1c = -10 + 2c

Solving
-20 + 1c = -10 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-20 + 1c + -2c = -10 + 2c + -2c

Combine like terms: 1c + -2c = -1c
-20 + -1c = -10 + 2c + -2c

Combine like terms: 2c + -2c = 0
-20 + -1c = -10 + 0
-20 + -1c = -10

Add '20' to each side of the equation.
-20 + 20 + -1c = -10 + 20

Combine like terms: -20 + 20 = 0
0 + -1c = -10 + 20
-1c = -10 + 20

Combine like terms: -10 + 20 = 10
-1c = 10

Divide each side by '-1'.
c = -10

Simplifying
c = -10

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