3c-2(c+2)=13-2(2c-5)

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Solution for 3c-2(c+2)=13-2(2c-5) equation:


Simplifying
3c + -2(c + 2) = 13 + -2(2c + -5)

Reorder the terms:
3c + -2(2 + c) = 13 + -2(2c + -5)
3c + (2 * -2 + c * -2) = 13 + -2(2c + -5)
3c + (-4 + -2c) = 13 + -2(2c + -5)

Reorder the terms:
-4 + 3c + -2c = 13 + -2(2c + -5)

Combine like terms: 3c + -2c = 1c
-4 + 1c = 13 + -2(2c + -5)

Reorder the terms:
-4 + 1c = 13 + -2(-5 + 2c)
-4 + 1c = 13 + (-5 * -2 + 2c * -2)
-4 + 1c = 13 + (10 + -4c)

Combine like terms: 13 + 10 = 23
-4 + 1c = 23 + -4c

Solving
-4 + 1c = 23 + -4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4c' to each side of the equation.
-4 + 1c + 4c = 23 + -4c + 4c

Combine like terms: 1c + 4c = 5c
-4 + 5c = 23 + -4c + 4c

Combine like terms: -4c + 4c = 0
-4 + 5c = 23 + 0
-4 + 5c = 23

Add '4' to each side of the equation.
-4 + 4 + 5c = 23 + 4

Combine like terms: -4 + 4 = 0
0 + 5c = 23 + 4
5c = 23 + 4

Combine like terms: 23 + 4 = 27
5c = 27

Divide each side by '5'.
c = 5.4

Simplifying
c = 5.4

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