3c-200+1c=2c+2c-150-50

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Solution for 3c-200+1c=2c+2c-150-50 equation: 


Simplifying
3c + -200 + 1c = 2c + 2c + -150 + -50

Reorder the terms:
-200 + 3c + 1c = 2c + 2c + -150 + -50

Combine like terms: 3c + 1c = 4c
-200 + 4c = 2c + 2c + -150 + -50

Reorder the terms:
-200 + 4c = -150 + -50 + 2c + 2c

Combine like terms: -150 + -50 = -200
-200 + 4c = -200 + 2c + 2c

Combine like terms: 2c + 2c = 4c
-200 + 4c = -200 + 4c

Add '200' to each side of the equation.
-200 + 200 + 4c = -200 + 200 + 4c

Combine like terms: -200 + 200 = 0
0 + 4c = -200 + 200 + 4c
4c = -200 + 200 + 4c

Combine like terms: -200 + 200 = 0
4c = 0 + 4c
4c = 4c

Add '-4c' to each side of the equation.
4c + -4c = 4c + -4c

Combine like terms: 4c + -4c = 0
0 = 4c + -4c

Combine like terms: 4c + -4c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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