3c-27=6(c-4)

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Solution for 3c-27=6(c-4) equation:



3c-27=6(c-4)
We move all terms to the left:
3c-27-(6(c-4))=0
We calculate terms in parentheses: -(6(c-4)), so:
6(c-4)
We multiply parentheses
6c-24
Back to the equation:
-(6c-24)
We get rid of parentheses
3c-6c+24-27=0
We add all the numbers together, and all the variables
-3c-3=0
We move all terms containing c to the left, all other terms to the right
-3c=3
c=3/-3
c=-1

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