3c-4c+1=5c+2(t-3)

Solution for 3c-4c+1=5c+2(t-3) equation:

Simplifying
3c + -4c + 1 = 5c + 2(t + -3)

Reorder the terms:
1 + 3c + -4c = 5c + 2(t + -3)

Combine like terms: 3c + -4c = -1c
1 + -1c = 5c + 2(t + -3)

Reorder the terms:
1 + -1c = 5c + 2(-3 + t)
1 + -1c = 5c + (-3 * 2 + t * 2)
1 + -1c = 5c + (-6 + 2t)

Reorder the terms:
1 + -1c = -6 + 5c + 2t

Solving
1 + -1c = -6 + 5c + 2t

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
1 + -1c + -5c = -6 + 5c + -5c + 2t

Combine like terms: -1c + -5c = -6c
1 + -6c = -6 + 5c + -5c + 2t

Combine like terms: 5c + -5c = 0
1 + -6c = -6 + 0 + 2t
1 + -6c = -6 + 2t

Add '-1' to each side of the equation.
1 + -1 + -6c = -6 + -1 + 2t

Combine like terms: 1 + -1 = 0
0 + -6c = -6 + -1 + 2t
-6c = -6 + -1 + 2t

Combine like terms: -6 + -1 = -7
-6c = -7 + 2t

Divide each side by '-6'.
c = 1.166666667 + -0.3333333333t

Simplifying
c = 1.166666667 + -0.3333333333t