3c-5(2c-7)=7(c+5)

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Solution for 3c-5(2c-7)=7(c+5) equation: 



3c-5(2c-7)=7(c+5)

We move all terms to the left:

3c-5(2c-7)-(7(c+5))=0

We multiply parentheses

3c-10c-(7(c+5))+35=0



We calculate terms in parentheses: -(7(c+5)), so:

7(c+5)

We multiply parentheses

7c+35

Back to the equation:

-(7c+35)



We add all the numbers together, and all the variables

-7c-(7c+35)+35=0

We get rid of parentheses

-7c-7c-35+35=0

We add all the numbers together, and all the variables

-14c=0

c=0/-14

c=0

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