3c-6=10-(5c-24)

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Solution for 3c-6=10-(5c-24) equation: 



3c-6=10-(5c-24)

We move all terms to the left:

3c-6-(10-(5c-24))=0



We calculate terms in parentheses: -(10-(5c-24)), so:

10-(5c-24)

determiningTheFunctionDomain
-(5c-24)+10

We get rid of parentheses

-5c+24+10

We add all the numbers together, and all the variables

-5c+34

Back to the equation:

-(-5c+34)



We get rid of parentheses

3c+5c-34-6=0

We add all the numbers together, and all the variables

8c-40=0

We move all terms containing c to the left, all other terms to the right

8c=40

c=40/8

c=5

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