3c-6=8+2(c+2)

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Solution for 3c-6=8+2(c+2) equation: 



3c-6=8+2(c+2)

We move all terms to the left:

3c-6-(8+2(c+2))=0



We calculate terms in parentheses: -(8+2(c+2)), so:

8+2(c+2)

determiningTheFunctionDomain
2(c+2)+8

We multiply parentheses

2c+4+8

We add all the numbers together, and all the variables

2c+12

Back to the equation:

-(2c+12)



We get rid of parentheses

3c-2c-12-6=0

We add all the numbers together, and all the variables

c-18=0

We move all terms containing c to the left, all other terms to the right

c=18

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