3c-7/5=c+2/2

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Solution for 3c-7/5=c+2/2 equation: 



3c-7/5=c+2/2

We move all terms to the left:

3c-7/5-(c+2/2)=0

We add all the numbers together, and all the variables

3c-(c+1)-7/5=0

We get rid of parentheses

3c-c-1-7/5=0

We multiply all the terms by the denominator


3c*5-c*5-7-1*5=0

We add all the numbers together, and all the variables

3c*5-c*5-12=0

Wy multiply elements

15c-5c-12=0

We add all the numbers together, and all the variables

10c-12=0

We move all terms containing c to the left, all other terms to the right

10c=12

c=12/10

c=1+1/5

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